P29_028 - 28 We consider the point at which it enters the...

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Unformatted text preview: 28. We consider the point at which it enters the field-filled region, velocity vector pointing downward. The field points out of the page so that v × B points leftward, which indeed seems to be the direction it is “pushed”; therefore, q > 0 (it is a proton). (a) Eq. 29-17 becomes T 2 130 × 10−9 which yields |B | = 0.252 T. = = 2πmp e |B | 2π 1.67 × 10−27 (1.60 × 10−19 ) |B | √ (b) Doubling the kinetic energy implies multiplying the speed by 2. Since the period T does√ not depend on speed, then it remains the same (even though the radius increases by a factor of 2). Thus, t = T /2 = 130 ns, again. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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