P29_032 - 32. (a) Since K = 1 mv 2 = 1 m(2Rfosc )2 m, 2 2...

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32. (a) Since K = 1 2 mv 2 = 1 2 m (2 πRf osc ) 2 m , K p = µ m p m d K d = 1 2 K d = 1 2 (17 MeV) = 8 . 5MeV . (b) We require a magnetic feld oF strength B p = 1 2 B d = 1 2 (1 . 6T)=0 . 80 T . (c) Since K B 2 /m , K 0 p = µ m d m p K d =2 K d =2(17MeV)=34MeV . (d) Since f osc = Bq/ (2 πm ) m 1 , f osc ,d = µ m d m P f osc ,p =2(12 × 10 6 s 1 )=2 . 4 × 10 7 Hz . (e) Now, K α = µ m α m d K d =2 K d =2(17MeV)=34MeV , B α = µ m α m d ¶µ q d q α B
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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