This preview shows page 1. Sign up to view the full content.
Unformatted text preview: 39. The applied field has two components: B x > 0 and B z > 0. Considering each straight-segment of the rectangular coil, we note that Eq. 29-26 produces a non-zero force only for the component of ~ B which is perpendicular to that segment; we also note that the equation is effectively multiplied by N = 20 due to the fact that this is a 20-turn coil. Since we wish to compute the torque about the hinge line, we can ignore the force acting on the straight-segment of the coil which lies along the y axis (forces acting at the axis of rotation produce no torque about that axis). The top and bottom straight-segments experience forces due to Eq. 29-26 (caused by the B z component), but these forces are (by the right-hand rule) in the ± y directions and are thus unable to produce a torque about the y axis. Consequently, the torque derives completely from the force exerted on the straight-segment located at x = 0 . 050 m, which has length L = 0 . 10 m and is shown in Figure 29-36 carrying current in the...
View Full Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08