Unformatted text preview: 50 cm side, the B x component produces a force i` y B x ˆ k, and there is no contribution from the B y component. Using SI units, the magnitude of the force on the ` y side is therefore (4 . 00 A)(0 . 500 m)(0 . 0692 T) = 0 . 138 N . On the 120 cm side, the B y component produces a force i` x B y ˆ k, and there is no contribution from the B x component. Using SI units, the magnitude of the force on the ` x side is also (4 . 00 A)(1 . 20 m)(0 . 0288 T) = 0 . 138 N . (b) The net force is i` y B x ˆ k + i` x B y ˆ k = 0 , keeping in mind that B x < 0 due to our initial assumptions. If we had instead assumed ~ B went the opposite direction of the current ﬂow in the hypotenuse, then B x > 0 but B y < 0 and a zero net force would still be the result....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08