P29_050 - 50. (a) = N Ai = r2 i = (0.150 m)2 (2.60 A) =...

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50. (a) µ = NAi = πr 2 i = π (0 . 150 m) 2 (2 . 60 A) = 0 . 184 A · m 2 . (b) The torque is τ = | × ~ B | = µB sin θ = ( 0 . 184 A
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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