P29_051 - 51. (a) The area of the loop is A = 1 (30 cm)(40...

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51. (a) The area of the loop is A = 1 2 (30 cm)(40 cm) = 6 . 0 × 10 2 cm 2 ,so µ = iA =(5 . 0A) ( 6 . 0 × 10 2 m 2 ) =0 . 30 A · m 2 . (b) The torque on the loop is τ
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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