P29_055 - 55. The magnetic dipole moment is = (0.60 0.80...

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55. The magnetic dipole moment is = µ (0 . 60 ˆ i 0 . 80 ˆ j), where µ = NiA = Niπr 2 =1(0 . 20A) π (0 . 080m) 2 = 4 . 02 × 10 4 A · m 2 .He re i is the current in the loop, N is the number of turns, A is the area of the loop, and r is its radius. (a) The torque is = × ~ B = µ (0 . 60 ˆ i 0 . 80 ˆ j) × (0 . 25 ˆ i+0 . 30 ˆ k) = µ h (0 . 60)(0 . 30)( ˆ i × ˆ k) (0 . 80)(0 . 25)( ˆ j × ˆ i) (0 . 80)(0 . 30)( ˆ j × ˆ k) i = µ [ 0 . 18 ˆ j+0 . 20 ˆ k 0 . 24 ˆ i] . Here ˆ i × ˆ k= ˆ j, ˆ j × ˆ i= ˆ k, and ˆ j × ˆ k= ˆ i are used. We also use ˆ i × ˆ i = 0. Now, we substitute the value for µ to obtain = ³ 0 . 97 × 10 4
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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