P29_069

# P29_069 - up and down directions. We assume B points up and...

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69. (a) We use Eq. 29-10: v d = E/B =(10 × 10 6 V / 1 . 0 × 10 2 m) / (1 . 5T)=6 . 7 × 10 4 m / s. (b) We rewrite Eq. 29-12 in terms of the electric Feld: n = Bi V`e = Bi ( Ed ) `e = Bi EAe which we use A = `d .I nt h i se x p e r im e n t , A =(0 . 010 m)(10 × 10 6 m) = 1 . 0 × 10 7 m 2 .B y Eq. 29-10, v d equals the ratio of the Felds (as noted in part (a)), so we are led to n = Bi EAe = i v d Ae = 3 . 0A (6 . 7 × 10 4 m / s)(1 . 0 × 10 7 m 2 )(1 . 6 × 10 19 C)
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Unformatted text preview: up and down directions. We assume B points up and the conductors width of 0 . 010 m is along an east-west line. We take the current going northward. The conduction electrons experience a westward magnetic force (by the right-hand rule), which results in the west side of the conductor being negative and the east side being positive (with reference to the Hall voltage which becomes established)....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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