P30_003 - 3. (a) The field due to the wire, at a point 8.0...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3. (a) The field due to the wire, at a point 8.0 cm from the wire, must be 39 µT and must be directed due south. Since B = µ0 i/2πr, i= 2πrB 2π (0.080 m)(39 × 10−6 T) = 16 A . = µ0 4π × 10−7 T · m/A (b) The current must be from west to east to produce a field which is directed southward at points below it. ...
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online