P30_023 - i 2 / 2 πr 2 where r 2 = 1 . 5 cm. From B P 1 =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
23. Using the right-hand rule, we see that the current i 2 carried by wire 2 must be out of the page. Now, B P 1 = µ 0 i 1 / 2 πr 1 where i 1 =6 . 5A and r 1 =0 . 75 cm + 1 . 5cm = 2 . 25 cm, and B P 2 = µ
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: i 2 / 2 πr 2 where r 2 = 1 . 5 cm. From B P 1 = B P 2 we get i 2 = i 1 µ r 2 r 1 ¶ = (6 . 5 A) µ 1 . 5 cm 2 . 25 cm ¶ = 4 . 3 A ....
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online