P30_024 - 24. We label these wires 1 through 5, left to...

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24. We label these wires 1 through 5, left to right, and use Eq. 30-15 (divided by length). Then, ~ F 1 = µ 0 i 2 2 π µ 1 d + 1 2 d + 1 3 d + 1 4 d ˆ j= 25 µ 0 i 2 24 πd ˆ j = (13)(4 π × 10 7 T · m / A)(3 . 00 A) 2 (1 . 00 m) ˆ j 24 π (8 . 00 × 10 2 m) =4 . 69 × 10 5 N / m ˆ j; ~ F 2 = µ 0 i 2 2 π µ 1 2 d
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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