P30_025 - 25. Each wire produces a field with magnitude...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 25. Each wire produces a field with magnitude given by B = µ0 i/2πr, where r is the distance from the corner of the square to the center. According to the Pythagorean theorem, the diagonal of the square √ √ √ has length 2a, so r = a/ 2 and B = µ0 i/ 2πa. The fields due to the wires at the upper left and lower right corners both point toward the upper right corner of the square. The fields due to the wires at the upper right and lower left corners both point toward the upper left corner. The horizontal components cancel and the vertical components sum to µ0 i 2 µ0 i cos 45◦ = 4√ πa 2πa −7 2(4π × 10 T · m/A)(20 A) = 8.0 × 10−5 T . = π (0.20 m) √ In the calculation cos 45◦ was replaced with 1/ 2. The total field points upward. B total = ...
View Full Document

Ask a homework question - tutors are online