P30_029 - b cancel out. or the remaining two (parallel)...

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29. The magnitudes of the forces on the sides of the rectangle which are parallel to the long straight wire (with i 1 = 30 A) are computed using Eq. 30-15, but the force on each of the sides lying perpendicular to it (along our y axis, with the origin at the top wire and + y downward) would be Fgured by integrating as follows: F sides = Z a + b a i 2 µ 0 i 1 2 πy dy . ±ortunately, these forces on the two perpendicular sides of length
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Unformatted text preview: b cancel out. or the remaining two (parallel) sides of length L , we obtain F = i 1 i 2 L 2 1 a 1 a + d = i 1 i 2 b 2 a ( a + b ) = (4 10 7 T m / A)(30 A)(20 A)(8 . 0 cm)(30 10 2 m) 2 (1 . 0 cm + 8 . 0 cm) = 3 . 2 10 3 N , and F points toward the wire....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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