P30_031 - associated with Amperes law. Thus, I ~ B d~s = i...

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31. (a) Two of the currents are out of the page and one is into the page, so the net current enclosed by the path is 2 . 0 A, out of the page. Since the path is traversed in the clockwise sense, a current into the page is positive and a current out of the page is negative, as indicated by the right-hand rule
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Unformatted text preview: associated with Amperes law. Thus, I ~ B d~s = i = (2 . 0 A)(4 10 7 T m / A) = 2 . 5 10 6 T m . (b) The net current enclosed by the path is zero (two currents are out of the page and two are into the page), so H ~ B d~s = i enc = 0....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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