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Unformatted text preview: 38. The ﬁeld at the center of the pipe (point C ) is due to the wire alone, with a magnitude of
BC = µ0 iwire
6πR For the wire we have BP, wire > BC, wire . Thus, for BP = BC = BC, wire , iwire must be into the page:
BP = BP, wire − BP, pipe =
Setting BC = −BP we obtain iwire = 3i/8 . µ0 iwire
2π (2R) ...
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- Fall '08