P30_038 - 38 The field at the center of the pipe(point C...

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Unformatted text preview: 38. The field at the center of the pipe (point C ) is due to the wire alone, with a magnitude of BC = µ0 iwire µ0 iwire = . 2π (3R) 6πR For the wire we have BP, wire > BC, wire . Thus, for BP = BC = BC, wire , iwire must be into the page: BP = BP, wire − BP, pipe = Setting BC = −BP we obtain iwire = 3i/8 . µ0 iwire µ0 i − . 2πR 2π (2R) ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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