P30_063 - equivalent to the expression in the problem...

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63. (a) Eq. 30-19 applies for each wire, with r = p R 2 +( d/ 2) 2 (by the Pythagorean theorem). The vertical components of the Felds cancel, and the two (identical) horizontal components add to yield the Fnal result B =2 µ µ 0 i 2 πr ¶µ d/ 2 r = µ 0 id 2 π ( R 2 +( d/ 2) 2 ) where ( d/ 2) /r is a trigonometric factor to select the horizontal component. It is clear that this is
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Unformatted text preview: equivalent to the expression in the problem statement. (b) Using the right-hand rule, we Fnd both horizontal components point rightward....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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