P30_065 - | ~ F | = L (5 . 0 A)(3 . 2 A) 2 (0 . 10 m) L (5...

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65. (a) All wires carry parallel currents and attract each other; thus, the “top” wire is pulled downward by the other two: | ~ F | = µ 0 L (5 . 0 A)(3 . 2 A) 2 π (0 . 10 m) + µ 0 L (5 . 0 A)(5 . 0A) 2 π (0 . 20m) where L =3 . 0m .Thus , | ~ F | =1 . 7 × 10 4
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Unformatted text preview: | ~ F | = L (5 . 0 A)(3 . 2 A) 2 (0 . 10 m) L (5 . 0 A)(5 . 0 A) 2 (0 . 20 m) so that | ~ F | = 2 . 1 10 5 N....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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