P30_070

P30_070 - cos 45 ◦ = 4 × 10 − 4 T and directed...

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70. We note that the distance from each wire to P is r = d/ 2=0 . 071 m. In both parts, the current is i = 100 A. (a) With the currents parallel, application of the right-hand rule (to determine each of their contribu- tions to the Feld at P ) reveals that the vertical components cancel and the horizontal components add – yielding the result: B =2 µ µ 0 i 2 πr
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Unformatted text preview: cos 45 ◦ = 4 . × 10 − 4 T . and directed leftward in the Fgure. (b) Now, with the currents antiparallel, application of the right-hand rule shows that the horizontal components cancel and the vertical components add. Thus, B = 2 µ µ i 2 πr ¶ sin 45 ◦ = 4 . × 10 − 4 T . and directed upward in the Fgure....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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