P31_003 - 3(a |E| = d dB =(6.0t2 7.0t = 12t 7.0 = 12(2.0...

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3. (a) |E| = ¯ ¯ ¯ ¯ d Φ B dt ¯ ¯ ¯ ¯ = d dt (6 . 0 t 2 +7 . 0 t )=12 t +7 . 0 = 12(2 . 0) + 7 . 0=31mV . (b) Appealing to Lenz’s law (especially Fig. 31-5(a)) we see that the current flow in the loop is clockwise.
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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