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14. We note that 1 gauss = 10
−
4
T. Adapting the result of the problem 11,
q
(
t
)=
N
R
[
BA
cos 20
◦
−
(
−
cos 20
◦
)] =
2
NBA
cos 20
◦
R
=
2(1000)(0
.
590
×
10
−
4
T)
π
(0
.
100 m)
2
(cos 20
◦
)
85
.
0 Ω + 140 Ω
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 Fall '08
 SPRUNGER
 Physics

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