P31_014 - 14. We note that 1 gauss = 104 T. Adapting the...

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14. We note that 1 gauss = 10 4 T. Adapting the result of the problem 11, q ( t )= N R [ BA cos 20 ( cos 20 )] = 2 NBA cos 20 R = 2(1000)(0 . 590 × 10 4 T) π (0 . 100 m) 2 (cos 20 ) 85 . 0 Ω + 140 Ω
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