This preview shows page 1. Sign up to view the full content.
Unformatted text preview: a 2 / 2 then the area (as it appears to us) enclosed by the circuit, as a function of our angle , is A = A + a 2 2 cos where (since is increasing at a steady rate) the angle depends linearly on time, which we can write either as = t or = 2 ft if we take t = 0 to be a moment when the arc is in the = 0 position. Since ~ B is uniform (in space) and constant (in time), Faradays law leads to E = d B dt = B dA dt = B d A + a 2 2 cos dt = B a 2 2 d cos(2 ft ) dt which yields E = B 2 a 2 f sin(2 ft ). This (due to the sinusoidal dependence) reinforces the conclu-sion in part (a) and also (due to the factors in front of the sine) provides the voltage amplitude: E max = B 2 a 2 f ....
View Full Document
- Fall '08