P31_021 - Z ` 4 t 2 y` dy = 2 t 2 ` 3 Thus ±araday’s law...

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21. Consider a (thin) strip of area of height dy and width ` =0 . 020 m. The strip is located at some 0 <y<` . The element of flux through the strip is d Φ B = BdA =(4 t 2 y )( `dy ) where SI units (and 2 signiFcant Fgures) are understood. To Fnd the total flux through the square loop, we integrate: Φ B = Z d Φ B =
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Unformatted text preview: Z ` ( 4 t 2 y` ) dy = 2 t 2 ` 3 . Thus, ±araday’s law yields |E| = ¯ ¯ ¯ ¯ d Φ B dt ¯ ¯ ¯ ¯ = 4 t` 3 . At t = 2 . 5 s, we Fnd the magnitude of the induced emf is 8 . × 10 − 5 V. Its “direction” (or “sense”) is clockwise, by Lenz’s law....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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