P31_030

# P31_030 - B = BA = (0 . 350)(5 . 20) 2 t 2 = 9 . 46 t 2 ....

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30. (a) The “height” of the triangular area enclosed by the rails and bar is the same as the distance traveled in time v : d = vt ,where v =5 . 20 m / s. We also note that the “base” of that triangle (the distance between the intersection points of the bar with the rails) is 2 d . Thus, the area of the triangle is A = 1 2 (base)(height) = 1 2 (2 vt )( vt )= v 2 t 2 . Since the Feld is a uniform B =0 . 350 T, then the magnitude of the ﬂux (in SI units) is Φ
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Unformatted text preview: B = BA = (0 . 350)(5 . 20) 2 t 2 = 9 . 46 t 2 . At t = 3 . 00 s, we obtain B = 85 . 2 Wb. (b) The magnitude of the emf is the (absolute value of) aradays law: E = d B dt = 9 . 46 dt 2 dt = 18 . 9 t in SI units. At t = 3 . 00 s, this yields E = 56 . 8 V. (c) Our calculation in part (b) shows that n = 1....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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