P31_030 - B = BA = (0 . 350)(5 . 20) 2 t 2 = 9 . 46 t 2 ....

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
30. (a) The “height” of the triangular area enclosed by the rails and bar is the same as the distance traveled in time v : d = vt ,where v =5 . 20 m / s. We also note that the “base” of that triangle (the distance between the intersection points of the bar with the rails) is 2 d . Thus, the area of the triangle is A = 1 2 (base)(height) = 1 2 (2 vt )( vt )= v 2 t 2 . Since the Feld is a uniform B =0 . 350 T, then the magnitude of the flux (in SI units) is Φ
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: B = BA = (0 . 350)(5 . 20) 2 t 2 = 9 . 46 t 2 . At t = 3 . 00 s, we obtain B = 85 . 2 Wb. (b) The magnitude of the emf is the (absolute value of) aradays law: E = d B dt = 9 . 46 dt 2 dt = 18 . 9 t in SI units. At t = 3 . 00 s, this yields E = 56 . 8 V. (c) Our calculation in part (b) shows that n = 1....
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online