P31_073 - 73. Letting the current in solenoid 1 be i, we...

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73. Letting the current in solenoid 1 be i , we calculate the flux linkage in solenoid 2. The mutual inductance, then, is this flux linkage divided by i . The magnetic feld inside solenoid 1 is parallel to the axis and has uniForm magnitude B = µ 0 in 1 ,whe re n 1 is the number oF turns per unit length oF the solenoid. The cross-sectional area oF the solenoid is πR 2 1 .S in c e ~ B is normal to the cross section, the flux here is Φ= AB = πR 2 1 µ 0
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