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Unformatted text preview: 96. We write (as functions of time) VL (t) = E e−t/τl . Considering the ﬁrst two data points, (VL1 , t1 ) and
(VL2 , t2 ), satisfying VLi = E e−ti /τL (i = 1, 2), we have VL1 /VL2 = E e−(t1 −t2 )/τL , which gives
τL = t1 − t2
1.0 ms − 2.0 ms
=
= 3.6 ms .
ln(V2 /V1 )
ln(13.8/18.2) Therefore, E = VL1 et1 /τL = (18.2 V)e1.0 ms/3.6 ms = 24 V. One can easily check that the values of τL and
E are consistent with the rest of the data points. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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