P31_100 - of the rod. In the case considered now the...

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100. (a) We apply Newton’s second law to the rod m dv dt = iBL , and integrate to obtain v = iBLt m . The velocity ±v points away from the generator G . (b) When the current i in the rod becomes zero, the rod will no longer be accelerated by a force F = iBL and will therefore reach a constant terminal velocity. This occurs when |E induced | = E . SpeciFcally, |E induced | = ¯ ¯ ¯ ¯ d Φ B dt ¯ ¯ ¯ ¯ = ¯ ¯ ¯ ¯ d ( BA ) dt ¯ ¯ ¯ ¯ = B ¯ ¯ ¯ ¯ dA dt ¯ ¯ ¯ ¯ = BvL = E . Thus, ±v = E /BL ,le ftward
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Unformatted text preview: of the rod. In the case considered now the battery initially supplies electric energy to the rod, causing its kinetic energy to increase to a maximum value of 1 2 mv 2 = 1 2 ( E /BL ) 2 . Afterwards, there is no further energy transfer from the battery to the rod, and the kinetic energy of the rod remains constant....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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