P28_036 - 90 − 1 = 167 Ω(d Since r = 20 0 Ω R R = 1...

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36. (a) Since i = E / ( r + R ext )and i max = E /r ,wehave R ext = R ( i max /i 1) where r =1 . 50 V / 1 . 00 mA = 1 . 50 × 10 3 . Thus, R ext =(1 . 5 × 10 3 Ω)(1 / 0 . 10 1) = 1 . 35 × 10 4 Ω; (b) R ext =(1 . 5 × 10 3 Ω)(1 / 0 . 50 1) = 1 . 50 × 10 3 Ω; (c) R ext =(1 . 5 × 10 3 Ω)(1
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Unformatted text preview: / . 90 − 1) = 167 Ω . (d) Since r = 20 . 0 Ω + R , R = 1 . 50 × 10 3 Ω − 20 . 0 Ω = 1 . 48 × 10 3 Ω....
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