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Unformatted text preview: 7. (a) At the magnetic equator (λm = 0), the ﬁeld is
B= 4π × 10−7 T · m/A (8.00 × 1022 A · m2 )
µ0 µ
=
= 3.10 × 10−5 T ,
3
4πr
4π (6.37 × 106 m)3 and φi = tan−1 (2 tan λm ) = tan−1 (0) = 0.
(b) At λm = 60◦ , we ﬁnd
B= µ0 µ
4πr3 1 + 3 sin2 λm = (3.10 × 10−5 ) 1 + 3 sin2 60◦ = 5.6 × 10−5 T , and φi = tan−1 (2 tan 60◦ ) = 74◦ .
(c) At the north magnetic pole (λm = 90.0◦ ), we obtain
B= µ0 µ
4πr3 1 + 3 sin2 λm = (3.1 × 10−5 ) 1 + 3(1.00)2 = 6.20 × 10−5 T , and φi = tan−1 (2 tan 90◦ ) = 90◦ . ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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