P32_021 - 21(a The field of a dipole along its axis is...

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Unformatted text preview: 21. (a) The field of a dipole along its axis is given by Eq. 30-29: B= µ0 µ , 2π z 3 where µ is the dipole moment and z is the distance from the dipole. Thus, B= (4π × 10−7 T · m/A)(1.5 × 10−23 J/T) = 3.0 × 10−6 T . 2π (10 × 10−9 m) (b) The energy of a magnetic dipole µ in a magnetic field B is given by U = −µ · B = −µB cos φ, where φ is the angle between the dipole moment and the field. The energy required to turn it end-for-end (from φ = 0◦ to φ = 180◦ ) is ∆U = 2µB = 2(1.5 × 10−23 J/T)(3.0 × 10−6 T) = 9.0 × 10−29 J = 5.6 × 10−10 eV . The mean kinetic energy of translation at room temperature is about 0.04 eV. Thus, if dipole-dipole interactions were responsible for aligning dipoles, collisions would easily randomize the directions of the moments and they would not remain aligned. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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