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Unformatted text preview: 35. (a) In region a of the graph,
id  =
= ε0 dE
dΦE
= ε0 A
dt
dt (8.85 × 10−12 F/m)(1.6 m2 ) 4.5 × 105 N/C − 6.0 × 105 N/C
= 0.71 A.
4.0 × 10−6 s (b) id ∝ dE/dt = 0.
(c) In region c of the graph,
id  = ε0 A dE
−4.0 × 105 N/C
= (8.85 × 10−12 F/m)(1.6 m2 )
= 1. 1 A .
dt
15 × 10−6 s − 10 × 10−6 s ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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