P32_039 - 39. (a) Using Eq. 27-10, we find E = ρJ = ρi...

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Unformatted text preview: 39. (a) Using Eq. 27-10, we find E = ρJ = ρi (1.62 × 10−8 Ω · m)(100 A) = 0.324 V/m . = A 5.00 × 10−6 m2 (b) The displacement current is dE d dΦE = ε0 A = ε0 A dt dt dt ρi A = ε0 ρ di dt = ε0 = id (8.85 × 10−12 F)(1.62 × 10−8 Ω)(2000 A/s) = 2.87 × 10−16 A . (c) The ratio of fields is µ0 id /2πr id 2.87 × 10−16 A B ( due to id ) = = = = 2.87 × 10−18 . B ( due to i) µ0 i/2πr i 100 A ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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