P32_050 - 50. (a) From Eq. 22-3, E= e (1.60 1019 C)(8.99...

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50. (a) From Eq. 22-3, E = e 4 πε 0 r 2 = (1 . 60 × 10 19 C)(8 . 99 × 10 9 N · m 2 / C 2 ) (5 . 2 × 10 11 m) 2 =5 . 3 × 10 11 N / C . (b) We use Eq. 30-28: B = µ 0 2 π µ p r 3 = ( 4 π × 10 7 T · m / A ) (1 . 4 × 10 26 J / T) 2 π (5 . 2 × 10 11 m) 3 =2 . 0 × 10 2 T . (c) From Eq. 32-10, µ
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