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Unformatted text preview: 1 2 m dx dt 2 + 1 2 kx 2 = const . , which yields = p k/m . So by analogy, in our case = r I = r B e I = s B e ml 2 / 12 , which leads to = ml 2 2 12 B e = (0 . 050 kg)(4 . 10 2 m) 2 (45 rad / s) 2 12(16 10 6 T) = 8 . 4 10 2 J / T ....
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 Fall '08
 SPRUNGER
 Physics, Conservation Of Energy, Energy, Potential Energy

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