p33_002 - 3 H)(4 . 00 10 6 F) = 4 . 52 10 2 A .

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2. According to U = 1 2 LI 2 = 1 2 Q 2 /C , the current amplitude is I = Q LC = 3 . 00 × 10 6 C p (1 . 10 × 10
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Unformatted text preview: 3 H)(4 . 00 10 6 F) = 4 . 52 10 2 A ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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