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27. The assumption stated at the end of the problem is equivalent to setting
φ
= 0 in Eq. 3325. Since the
maximum energy in the capacitor (each cycle) is given by
q
2
max
/
2
C
,where
q
max
is the maximum charge
(during a given cycle), then we seek the time for which
q
2
max
2
C
=
1
2
Q
2
2
C
=
⇒
q
max
=
Q
√
2
.
Now
q
max
(referred to as the
exponentially decaying amplitude
in
§
335) is related to
Q
(and the other
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Charge, Energy

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