p33_044 - 44. (a) The capacitive reactance is XC = 1 1 = =...

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44. (a) The capacitive reactance is X C = 1 2 πfC = 1 2 π (400 Hz)(24 . 0 × 10 6 F) =16 . 6Ω . (b) The impedance is Z = p R 2 +( X L X C ) 2 = p R 2 +(2 πfL X C ) 2 = p (220 Ω) 2 +[2 π (400 Hz)(150 × 10 3 H) 16 . 6Ω] 2 = 422 Ω . (c) The current amplitude is I = E m Z = 220 V 422 Ω =0 . 521 A . (d) Now X C C 1 eq .Thu s , X C increases as C eq
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