p33_047 - 47. We use the expressions found in Problem 45: +...

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47. We use the expressions found in Problem 45: ω 1 = + 3 CR + 3 C 2 R 2 +4 LC 2 LC ω 2 = 3 CR + 3 C 2 R 2 +4 LC 2 LC . We also use Eq. 33-4. Thus, ω d ω = ω 1 ω 2 ω = 2 3 CR LC 2 LC = R r 3 C L . For the data of Problem 45, ω d ω =(5 . 00 Ω) r 3(20 . 0 × 10 6 F) 1 . 00 H =3 . 87 × 10 2 . This is in agreement with the result of Problem 45. The method of Problem 45, however, gives only one
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