p33_049 - i d is direct is given by P = i 2 d R . Setting...

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49. The average power dissipated in resistance R when the current is alternating is given by P avg = I 2 rms R , where I rms is the root-mean-square current. Since I rms = I/ 2, where I is the current amplitude, this can be written P avg = I 2 R/ 2. The power dissipated in the same resistor when the current
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Unformatted text preview: i d is direct is given by P = i 2 d R . Setting the two powers equal to each other and solving, we obtain i d = I √ 2 = 2 . 60 A √ 2 = 1 . 84 A ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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