p33_053 - . 14 W . P avg = 1 2 I 2 R = 1 2 (0 . 151 A) 2...

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53. We use P avg = I 2 rms R = 1 2 I 2 R. P avg = 0, since R =0. P avg = 1 2 I 2 R = 1 2 (0 . 600 A) 2 (50 Ω) = 9 . 0W . P avg = 1 2 I 2 R = 1 2 (0 . 198 A) 2 (160 Ω) = 3
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Unformatted text preview: . 14 W . P avg = 1 2 I 2 R = 1 2 (0 . 151 A) 2 (160 ) = 1 . 82 W ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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