This preview shows page 1. Sign up to view the full content.
78. (a) The voltage amplitude for the source is
V
s
= 100 V =
IZ
=
I
p
R
2
+
X
2
C
,f
romwh
i
chw
ecan
determine the current at each frequency (the explicit dependence of
X
C
on frequency is stated in
the solution to part (a) of problem 77). This leads to the voltage amplitude across the resistor
V
R
=
IR
and the voltage amplitude across the capacitor
V
C
=
IX
C
=
Ã
V
s
p
R
2
+
X
2
C
!
X
C
where
X
C
=
1
2
πCf
using the values
R
= 200 Ω and
C
=45
×
This is the end of the preview. Sign up
to
access the rest of the document.
Unformatted text preview: of V s , V R and V C over the range 0 < f < 100 Hz. The falling curve is V C and the rising curve is V R . 20 40 60 80 100 2 4 6 8 1 f (b) The graph indicates that V C and V R are equal at roughly 18 Hz. More careful considerations lead to f = 17 . 7 Hz as the frequency for which V C = V R ....
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Current

Click to edit the document details