p33_081 - 81. (a) We find L from XL = ωL = 2πf L: f= XL...

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Unformatted text preview: 81. (a) We find L from XL = ωL = 2πf L: f= XL 1.30 × 103 Ω = = 4.60 × 103 Hz . 2πL 2π (45.0 × 10−3 H) (b) The capacitance is found from XC = (ωC )−1 = (2πf C )−1 : C= 1 1 = 2.66 × 10−8 F . = 2πf XC 2π (4.60 × 103 Hz)(1.30 × 103 Ω) (c) Noting that XL ∝ f and XC ∝ f −1 , we conclude that when f is doubled, XL doubles and XC reduces by half. Thus, XL = 2(1.30 × 103 Ω) = 2.60 × 103 Ω and XC = 1.30 × 103 Ω/2 = 6.50 × 102 Ω. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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