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87. (a) We observe that
ω
= 6597 rad/s, and, consequently,
X
L
= 594 Ω and
X
C
=303Ω.S
ince
X
L
>X
C
,
the phase angle is positive:
φ
=+60
◦
.
(b) From Eq. 3365, we obtain
R
=
X
L
−
X
C
tan
φ
= 168 Ω
.
(c) Since we are already on the “high side” of resonance, increasing
f
will only decrease the current
further, but
decreasing
f
brings us closer to resonance and, consequently, large values of
I
.
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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