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92.
(a) From Eq. 334, with
ω
=2
πf
,wehave
f
=
1
2
π
√
LC
=7
.
08
×
10
−
3
H
.
(b) The maximum current in the oscillator is
i
max
=
I
C
=
V
C
X
C
=
ωCv
max
=4
.
00
×
10
−
3
A
.
(c) Using Eq. 3151, we fnd the maximum magnetic energy:
U
B,
max
=
1
2
Li
2
max
=1
.
6
×
10
−
8
J
.
(d) Adapting Eq. 3137 to the notation o± this chapter,
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Current, Energy

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