p34_003 - 3. (a) From Fig. 34-2 we find the wavelengths in...

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Unformatted text preview: 3. (a) From Fig. 34-2 we find the wavelengths in question to be about 515 nm and 610 nm. (b) Again from Fig. 34-2 the wavelength is about 555 nm. Therefore, f= c 3.00 × 108 m/s = = 5.41 × 1014 Hz , λ 555 nm and the period is (5.41 × 1014 Hz)−1 = 1.85 × 10−15 s. ...
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