p34_024 - 24. (a) We note that the cross section area of...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
24. (a) We note that the cross section area of the beam is πd 2 / 4, where d is the diameter of the spot ( d =2 . 00 λ ). The beam intensity is I = P 2 / 4 = 5 . 00 × 10 3 W π [(2 . 00)(633 × 10 9 m)] 2 / 4 =3 . 97 × 10 9 W / m 2 . (b) The radiation pressure is p r = I c = 3 . 97 × 10 9 W / m 2 2 . 998 × 10 8 m / s =13 . 2Pa . (c) In computing the corresponding force, we can use the power and intensity to eliminate the area (mentioned in part (a)). We obtain F
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online