p34_026 - 26 The mass of the cylinder is m =(d2/4)H where...

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26. The mass of the cylinder is m = ρ ( πd 2 1 / 4) H ,whe re d 1 is the diameter of the cylinder. Since it is in equilibrium F net = mg F r = πHd 2 1 4 µ πd 2 1 4 ¶µ 2 I c =0 . We solve for H : H = 2 I gcρ = µ 2 P πd 2 / 4 1
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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