p34_040 - I f I = E 2 h E 2 v + E 2 h = (2 . 3 E v ) 2 E 2...

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40. (a) The fraction of light which is transmitted by the glasses is I f I 0 = E 2 f E 2 0 = E 2 v E 2 v + E 2 h = E 2 v E 2 v +(2 . 3 E v ) 2 =0 . 16 . (b) Since now the horizontal component of ~ E will pass through the glasses,
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Unformatted text preview: I f I = E 2 h E 2 v + E 2 h = (2 . 3 E v ) 2 E 2 v + (2 . 3 E v ) 2 = 0 . 84 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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