p34_064 - . 50 ns (pulse travel time in soil) from the...

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64. (a) The 63 . 00 ns arrival times are consistent with the top of the tomb being 31 . 50 ns (pulse travel time) away from the surface. Since the pulses travel at 10 . 0 cm/ns in the soil, this travel time corresponds to a distance equal to 315 cm = 3 . 15 m. (b) We are told that the locations in Fig. 34-54 are 2 . 0 m apart. Return pulses are registered at stations 2 through 7, but the returns from stations 2 and 7 are not “robust.” The tomb’s horizontal length is therefore at least 9 m long, and very probably less than 12 m in length. (c) As demonstrated in part (a), we divide the travel times by 2 to infer depth. Thus, at station 3: the top of the tomb is 31
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Unformatted text preview: . 50 ns (pulse travel time in soil) from the surface; the top stone slab is 1 . 885 ns thick (pulse travel time in stone); the interior of the tomb is 8 . 00 ns high (pulse travel time in air); and the bottom stone slab is 1 . 885 ns thick (pulse travel time in stone). Since the pulse travels at 30 cm / s in the air, the interior of the tomb under station 3 (at the west end of the tomb) is 240 cm = 2 . 40 m high. At the east end (under, say, station 5), the corresponding time dierence is 74 . 77 ns 66 . 77 ns 2 = 4 . 00 ns which corresponds to an interior height equal to (4 . 00 ns)(30 cm / s) = 120 cm / s = 1 . 20 m....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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