p34_065 - 65. Since the layers are parallel, the angle of...

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Unformatted text preview: 65. Since the layers are parallel, the angle of refraction regarding the first surface is the same as the angle of incidence regarding the second surface (as is suggested by the notation in Fig. 34-55). We recall that as part of the derivation of Eq. 34-49 (Brewster’s angle), the textbook shows that the refracted angle is the complement of the incident angle: θ2 = (θ1 )c = 90◦ − θ1 . We apply Eq. 34-49 to both refractions, setting up a product: n2 n1 n3 n2 n3 n1 = (tan θB 1→2 ) (tan θB 2→3 ) = (tan θ1 ) (tan θ2 ) . Now, since θ2 is the complement of θ1 we have tan θ2 = tan(θ1 )c = 1 . tan θ1 Therefore, the product of tangents cancel and we obtain n3 /n1 = 1. Consequently, the third medium is air: n3 = 1.0. ...
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