p34_065

# p34_065 - 65 Since the layers are parallel the angle of...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 65. Since the layers are parallel, the angle of refraction regarding the ﬁrst surface is the same as the angle of incidence regarding the second surface (as is suggested by the notation in Fig. 34-55). We recall that as part of the derivation of Eq. 34-49 (Brewster’s angle), the textbook shows that the refracted angle is the complement of the incident angle: θ2 = (θ1 )c = 90◦ − θ1 . We apply Eq. 34-49 to both refractions, setting up a product: n2 n1 n3 n2 n3 n1 = (tan θB 1→2 ) (tan θB 2→3 ) = (tan θ1 ) (tan θ2 ) . Now, since θ2 is the complement of θ1 we have tan θ2 = tan(θ1 )c = 1 . tan θ1 Therefore, the product of tangents cancel and we obtain n3 /n1 = 1. Consequently, the third medium is air: n3 = 1.0. ...
View Full Document

## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online