This preview shows page 1. Sign up to view the full content.
Unformatted text preview: sin N sin f . We see that the L.H.S. of the equation above can be reduced to n /n while the R.H.S. is equal to sin i / sin f . Equating these two expressions, we Fnd sin f = n n sin i = sin i , which gives i = f . So for the two light rays in the problem statement, the angle of the emerging light rays are both the same as their respective incident angles. Thus, f = 0 for ray a and f = 20 for ray b . (b) In this case, all we need to do is to change the value of n from 1.0 (for air) to 1.5 (for glass). This does not change the result above. Note that the result of this problem is fairly general. It is independent of the number of layers and the thickness and index of refraction of each layer....
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Light

Click to edit the document details